If the ASCII character 'G' is transmitted but the receiver interprets it as 'D', what type of transmission error best describes this situation (analyze the bit pattern change)?

Introduction / Context:
Error classifications help diagnose channel issues and select suitable detection/correction schemes. When a transmitted character turns into another, the difference in their binary codes reveals whether the corruption affected one bit, several bits scattered, or a contiguous run (burst).

Given Data / Assumptions:

• Transmitted: ‘’G’’ (ASCII 0x47 = 0100 0111 in 7-bit plus parity or 8-bit form).
• Received: ‘’D’’ (ASCII 0x44 = 0100 0100).
• Assume standard ASCII and negligible framing/parity overhead for this classification.

Concept / Approach:
Compare the binary patterns. G = 0100 0111 and D = 0100 0100 differ in the two least-significant bits: 11 -> 00. Two adjacent bit positions changed, which is characteristic of a short burst error (contiguous bits corrupted).

Step-by-Step Solution:
Write binary: G = 0100 0111.Write binary: D = 0100 0100.Identify differences: bit0 and bit1 (LSBs) flipped from 1 to 0.Adjacent flips imply a burst of length 2 rather than an isolated single-bit error.

Verification / Alternative check:
Hamming distance between G and D is 2. Because the flipped bits are contiguous, it aligns with “burst” classification (a run of bits altered). If the two flipped bits were far apart, it would be multiple-bit non-burst.

Why Other Options Are Wrong:
single-bit: Only one bit differs; here two do.

multiple-bit: True that multiple bits changed, but “burst” is a more precise classification given adjacency.

recoverable: Not a standard error type; recoverability depends on coding.

framing: Concerns start/stop/flag alignment, not symbol bit flips.

Common Pitfalls:
Equating any 2-bit error with generic “multiple-bit.” When adjacency exists, “burst” conveys cause (e.g., short noise spike).

Final Answer:
burst