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The sum of length, breadth and depth of a cuboid is 19 cm and its diagonal is 5√ 5 cm. Its surface area would be?

Correct Answer: 246 m2

Explanation:

L + B + H = 19 cm, where L is the length, B is the breadth and
H is the height of the cuboid.
∴ (√L2 + B2 + H2
= (5√5)
On squaring both sides, we get
L2 + B2 + H2 + = 125
(L + B + H)2 = L2 + B2 + H2 + 2LB + 2LH + 2BH
⇒ (19)2 = 125 + 2(LB + LH + BH)
∴ Surface area = 2(LB + LH + BH)
= 192 = 125 + 2(LB + LH + BH)
= 192 - 125 = 361 - 125 = 192 - 125
= 361 - 125 = 236 cm2


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