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If the radius of base and height of a cone are increased by 10%, find the percentage of increase of its volume

33.5%
33.1%
32.1%
53.1%

Correct Answer: 33.1%

Explanation:

v1= $\frac{1}{3} πr 12 h 1$

v2= $\frac{1}{3} πr 22 h 2$

% Increase in volume = (V2-V1) / (V2*100)

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