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A rectangular block has the dimensions 5x6x7 cm it is dropped into a cylindrical vessel of radius 6cm and height 10 cm. If the level of the fluid in the cylinder rises by 4 cm, What portion of the block is immersed in the fluid ?

Correct Answer: 22/7 x 24/35

Explanation:

Since level of water increased in cylinder by height 4. 


This is because of the rectangular block .


 


Therefore , area of rectangular block immersed in water is 


= 22 7 × 6 × 6 × 4   


Thats why portion of block immersed in water is 


= (22/7 * 36 * 4) / total vol. of rectangle 


= (22/7 * 36 * 4)/ (7*5*6) 


= (22/7 * 24)/ 35.


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