K can finish the work in 18 days and L can do the same work in 15 days. L worked for 10 days and left the job. In how many days, K alone can finish the remaining work ?

Q: K can finish the work in 18 days and L can do the same work in 15 days. L worked for 10 days and left the job. In how many days, K alone can finish the remaining work ?

L's 10 days work = 1 15 × 10 = 2 3 Remaining work = 1 - 2 3 = 1 3 Now, work is done by K in one day = 1/18 1/3 work is done by K in 18 × 1 3 = 6 days

5.5 days
6 days
4.2 days
5 days

Correct Answer: 6 days

Explanation:

L's 10 days work = $\frac{1}{15} \times 10 = \frac{2}{3}$

Remaining work = $1 - \frac{2}{3} = \frac{1}{3}$

Now, work is done by K in one day = 1/18

1/3 work is done by K in $18 \times \frac{1}{3}$ = 6 days

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