A dishonest dealer sells articles at 10% loss on cost price but uses the weight of 16g instead of 18g. What is his profit or loss per cent?

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Accepted Answer

Given that a = 10% , b = 16g and c = 18g
= [(100 - a)c /b - 100)]%
= [(100 - 10) x 18/16 - 100]%
= [90 x 18/16 - 100]%
= [90 x 9/8 - 100]%
= 810/8 - 100 %
= (810 - 800) / 8 %
= 10/8 % = 5/4 %
=1^1<…

A dishonest dealer sells articles at 10% loss on cost price but uses the weight of 16g instead of 18g. What is his profit or loss per cent?

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