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Two trains are running at 60 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 6 seconds. What is the length of the fast train ? A. 6623 mts B. 6632 mts C.6345 mts D. 6354 mts

Option A
Option B
Option C
Option D

Correct Answer: Option A

Explanation:

As Trains are moving in same direction,

Relative Speed = 60-20 = 40 kmph

--> $40 \times \frac{5}{18} = \frac{100}{9}$ m/sec

Length of Train= Speed * Time

Length = $\frac{100}{9} \times 6$

$\Rightarrow \frac{200}{3} = 66 \frac{2}{3} m t s$

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