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Find the length of a train if it takes 10 seconds to cross a pole and double of this time to cross a platform of length 200 mts ?

Correct Answer: 200 mts

Explanation:

Let the length of the train be 'L' mts


let the speed of the train be 'S' m/s


Given it crosses a pole in 10 sec=> L/S = 10 ......(1)
Given it takes 20 sec (double of pole) to cross a platform of length 200 mts


=> (L + 200)/S = 20


=> L/S + 200/S = 20


But from (1) L/S = 10


=> 200/S = 20 - 10


=> S = 20 m/s


Then, from (1)


=> L = 10 x 20 = 200 mts.


Hence, the length of the train = 200 mts.


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