Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:

36
45
48
49

Correct Answer: 48

Explanation:

Relative speed = (60+ 90) km/hr

=	❨	150 x	5	❩m/sec
			18

=	❨	125	❩m/sec.
		3

Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.

Required time =	❨	2000 x	3	❩sec = 48 sec.
			125

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