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Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:

Correct Answer: 48

Explanation:

Relative speed = (60+ 90) km/hr


   = 150 x 5 ❩m/sec
18



   = 125 ❩m/sec.
3


Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.



Required time = 2000 x 3 ❩sec = 48 sec.
125
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