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Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?

Difficulty: Medium

9:30 a.m.
10:00 a.m.
10:30 a.m.
11:00 a.m.

Correct Answer: 10:00 a.m.

Explanation:

Given Data

Distance AB = 110 km
A→B train: 20 km/hr starting 7 a.m.
B→A train: 25 km/hr starting 8 a.m.

Step 1: Staggered start
By 8 a.m., A→B train covers 20 × 1 = 20 km.Remaining distance at 8 a.m. = 110 − 20 = 90 km.

Step 2: Relative speed towards each other
v_rel = 20 + 25 = 45 km/hrTime after 8 a.m. = 90 ÷ 45 = 2 h

Final Answer
Meet at 10:00 a.m.

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