Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?

Given Data

• Distance between A and B = 110 km
• Train from A starts at 7 a.m. at 20 km/hr
• Train from B starts at 8 a.m. at 25 km/hr
• Required: meeting time

Step 1: Account for the staggered start
By 8 a.m., the A→B train has already covered 20 × 1 = 20 km.Remaining separation at 8 a.m. = 110 − 20 = 90 km.

Step 2: Use relative speed towards each other
Relative speed = 20 + 25 = 45 km/hrTime after 8 a.m. to meet = 90 ÷ 45 = 2 hours

Final Answer
They meet at 10:00 a.m.