A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:

48 km/hr
54 km/hr
66 km/hr
82 km/hr

Correct Answer: 82 km/hr

Explanation:

Let the speed of the second train be x km/hr.

Relative speed

= (x + 50) km/hr

=	[	(x + 50) x	5	]	m/sec
			18

=	[	250 + 5x	]	m/sec.
		18

Distance covered = (108 + 112) = 220 m.

∴

220

= 6

❨	250 + 5x	❩
	18

⟹ 250 + 5x = 660

⟹ x = 82 km/hr.

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