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A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:

Correct Answer: 82 km/hr

Explanation:

Let the speed of the second train be x km/hr.


Relative speed = (x + 50) km/hr
= [ (x + 50) x 5 ] m/sec
18
= [ 250 + 5x ] m/sec.
18


Distance covered = (108 + 112) = 220 m.



220 = 6
250 + 5x
18


⟹ 250 + 5x = 660


x = 82 km/hr.


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