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The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:

1008
1015
1022
1032

Correct Answer: 1015

Explanation:

Required number = (L.C.M. of 12,16, 18, 21, 28) + 7

= 1008 + 7

= 1015

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