Home » Aptitude » Problems on H.C.F and L.C.M

Find the lowest common multiple of 24, 36 and 40.

Q: Find the lowest common multiple of 24, 36 and 40.

2 | 24 - 36 - 40 -------------------- 2 | 12 - 18 - 20 -------------------- 2 | 6 - 9 - 10 ------------------- 3 | 3 - 9 - 5 ------------------- | 1 - 3 - 5 L.C.M. = 2 x 2 x 2 x 3 x 3 x 5 = 360.

Correct Answer: 360

Explanation:

 2 | 24  -  36  - 40
 --------------------
 2 | 12  -  18  - 20
 --------------------
 2 |  6  -   9  - 10
 -------------------
 3 |  3  -   9  -  5
 -------------------
   |  1  -   3  -  5
   
L.C.M.  = 2 x 2 x 2 x 3 x 3 x 5 = 360.

← Previous Question Next Question→

More Questions from Problems on H.C.F and L.C.M

The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:
A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. After what time will they again at the starting point?
Reduce 128352/238368 to its lowest terms
The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:
Three number are in the ratio of 3 : 4 : 5 and their L.C.M. is 2400. Their H.C.F. is:
What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30?
The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:
The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:
Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together?
Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:

Discussion & Comments

No comments yet. Be the first to comment!

Join Discussion