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Three unbiased coins are tossed.What is the probability of getting at least 2 heads?

Correct Answer: 1/2

Explanation:

Here S= {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}.


Let E = event of getting at least two heads = {THH, HTH, HHT, HHH}.


P(E) = n(E) / n(S)


      = 4/8= 1/2


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