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Three unbiased coins are tossed, what is the probability of getting exactly two heads?

1/3
3/4
2/3
3/8

Correct Answer: 3/8

Explanation:

S= { HHH, HHT, HTH, THH, TTH, THT, HTT, TTT} and
E = Event of getting exactly two heads = {HHT, HTH, THH}
∴ P(E) = n(E)/n(S) = 3/8

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