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In a simultaneous throw of two coins, the probability of getting at least one head is?

1/2
2/3
3/4
1/3

Correct Answer: 3/4

Explanation:

S = {HH, HT, TT, TH}
and E = {HH, HT, TH }
∴ P(E) = n(E)/n(S) = 3/4

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