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The probabilities that drivers A, B and C will drive home safely after consuming liquor are 2 / 5, 3 / 7 and 3 / 4, respectively. What is the probability that they will drive home safely after consuming liquor ?

Correct Answer: 9/70

Explanation:

Let A be the event of driver A drive safely after consuming liquor. 


 


Let B be the event of driver B drive safely after consuming liquor. 


 


Let C be the event of driver C drive safely after consuming liquor. 


 


P(A)=2/5,P(B)=3/7,P(C)=3/4


 


The events A, B and C are independent . Therefore,


 


P A B C = P ( A ) P ( B ) P ( C ) = 2 5 * 3 7 * 3 4 = 9 70


 


Therefore, The probability that all the drivers will drive home safely after consuming liquor is 9/70


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