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Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is:

Correct Answer: 14

Explanation:

Part filled in 2 hours = 2/6=1/3


 


Remaining part = 1 - 1 3 = 2 3


 


 (A + B)'s 7 hour's work = 2/3


 


(A + B)'s 1 hour's work = 2/21


 


C's 1 hour's work = { (A + B + C)'s 1 hour's work } - { (A + B)'s 1 hour's work }


 


=1/6-2/21 = 1/14


 


C alone can fill the tank in 14 hours.


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