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Pipes A and B fill a tank in 5 h and 6 h; pipe C empties it in 12 h. If all three are opened together, how long will the tank take to fill?

Difficulty: Medium

Correct Answer: 3 9/17 hours (approx. 3 h 31 m 46 s)

Explanation:

Problem restatement
Combine two inlet rates and one outlet rate to get net fill time.


Given data

  • A = 1/5 per h
  • B = 1/6 per h
  • C (outlet) = 1/12 per h

Concept/Approach
Net rate = A + B − C. Time = 1 / (net rate).


Step-by-step calculation
Net rate = 1/5 + 1/6 − 1/12= (12 + 10 − 5)/60 = 17/60 per hourTime = 1 / (17/60) = 60/17 hours = 3 9/17 hours ≈ 3 h 31 m 46 s


Verification/Alternative
Check net positivity: 1/5 + 1/6 > 1/12, so the tank fills.


Common pitfalls
Adding times instead of rates, or subtracting 1/12 from only one inlet.


Final Answer
3 9/17 hours (≈ 3 h 31 m 46 s)

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