Two pipes A and B can fill a tank in 15 minutes and 20 minutes respectively. Both the pipes are opened together but after 4 minutes, pipe A is turned off. What is the total time required to fill the tank?

Correct Answer: 14 min. 40 sec.

Explanation:

Part filled in 4 minutes = 4	❨	1	+	1	❩	=	7	.
		15		20			15

Remaining part =	❨	1 -	7	❩	=	8	.
			15			15

Part filled by B in 1 minute =	1
	20

∴	1	:	8	:: 1 : x
	20		15

x =	❨	8	x 1 x 20	❩	= 10	2	min = 10 min. 40 sec.
		15				3

∴ The tank will be full in (4 min. + 10 min. + 40 sec.) = 14 min. 40 sec.

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