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The number of sequences in which 4 players can sing a song, so that the youngest player may not be the last is ?

Correct Answer: 4320

Explanation:

Let 'Y' be the youngest player.


The last song can be sung by any of the remaining 3 players. The first 3 players can sing the song in (3!) ways.


The required number of ways = 3(3!) = 4320.


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