Home » Aptitude » Permutation and Combination

A box contains 2 blue balls, 3 green balls and 4 yellow balls. In how many ways can 3 balls be drawn from the box, if at least one green ball is to be included in the draw?

Correct Answer: 64

Explanation:

Total number of balls = 2 + 3 + 4 = 9


Total number of ways 3 balls can be drawn from 9 = 9C3


No green ball is drawn = 9 - 3 = 6 = 6C3


Required number of ways if atleast one green ball is to be included = Total number of ways - No green ball is drawn


= 9C3 - 6C3


= 9x8x7/3x2  -  6x5x4/3x2


= 84 - 20


= 64 ways.


← Previous Question Next Question→

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion