A district has 64000 inhabitants. If the population increases at the rate of 2 * 1/2 % per annum, then the number of inhabitants at the end of 3 years will be :

65380
68921
70987
72345

Correct Answer: 68921

Explanation:

Population afer 3 years = 64000 * (1 + 5/(2 *100) )^3 = (64000 * 41/40 * 41/40 * 41/40 ) = 68921..

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