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A bag contains 600 coins of 25 p denomination and 1200 coins of 50 p denomination. If 12% of 25 p coins and 24% of 50 p coins are removed, the percentage of money removed from the bag is nearly :

Correct Answer: 21.6 %

Explanation:

Total money = Rs.[600*(25/100)+1200*(50/100)]= Rs. 750.


 


25 paise coins removed = Rs. (600*12/100) = 72.


 


50 paise coins removed = Rs. (1200*24/100)= 288.


 


Money removed =Rs.(72*25/100+288*50/100)  = Rs.162.


 


Required percentage = (162/750*100)% = 21.6 %.


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