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The equation log ax + log a (1+x)=0 can be written as?

Correct Answer: x2 + x - 1 = 0

Explanation:

logax + loga(1+x) = 0
⇒ logax (x+1) = loga1 (since log 1 = 0)
⇒ x(x +1) = 1
∴ x2 + x - 1 = 0


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