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If 2log 4x = 1 + log 4 (x-1), find the value of x.?

Correct Answer: 2

Explanation:

∵ 2log4x = 1 + log4(x-1)
⇒ log4x2 = log44 + log4(x-1)
⇒ x2 = 4(x-1)
⇒ x2 - 4x + 4 = 0
⇒ (x-2)2 = 0
∴ x = 2


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