In a triangle ABC, BC = 5 cm AC = 12 cm and AB = 13 cm. The length of a altitude drawn from B on AC is?

Question

Accepted Answer

∵ s= (13 + 5 + 12) / 2 cm = 15cm s-a = 2 cm, s-b = 10 cm and s-c = 3 cm ⇒ Area = √ (15 x 2 x 10 x 3 ) cm2 = 30 cm2 ⇒ (12 x h) / 2 = 30 ∴ h = 5 cm

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