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In a triangle ABC, BC = 5 cm AC = 12 cm and AB = 13 cm. The length of a altitude drawn from B on AC is?

Correct Answer: 5 cm

Explanation:

∵ s= (13 + 5 + 12) / 2 cm
= 15cm
s-a = 2 cm,
s-b = 10 cm and
s-c = 3 cm
⇒ Area = √ (15 x 2 x 10 x 3 ) cm2
= 30 cm2
⇒ (12 x h) / 2 = 30
∴ h = 5 cm


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