Find the area of a triangle whose sides measure 13 cm, 14 cm and 15 cm.

Q: Find the area of a triangle whose sides measure 13 cm, 14 cm and 15 cm.

Let a = 13, b = 14 and c = 15. Then, s = 1 2 a + b + c =21 (s- a) = 8, (s - b) = 7 and (s - c) = 6. Area = s s - a s - b s - c = 21 × 8 × 7 × 6 = 84 sq.cm

84
64
44
22

Correct Answer: 84

Explanation:

Let a = 13, b = 14 and c = 15. Then, $s = \frac{1}{2} a + b + c$ =21

(s- a) = 8, (s - b) = 7 and (s - c) = 6.

Area = $s s - a s - b s - c$ = $21 \times 8 \times 7 \times 6$ = 84 sq.cm

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