Three circles of radius 3.5cm are placed in such a way that each circle touches the other two. The area of the portion enclosed by the circles is

1.967
1.867
1.767
1.567

Correct Answer: 1.967

Explanation:

required area = (area of an equilateral triangle of side 7 cm)- (3 * area of sector with Ã = 60 degrees and r = 3.5cm)
$\frac{3}{4} * 7 * 7 - 3 * \frac{22}{7} * 3.5 * 3.5 * \frac{60}{360}$ sq cm

= $\frac{3}{4} * 49 - 11 * 0.5 * 3.5$ sq cm

= 1.967 sq cm

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