A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?

Correct Answer: 6 litres, 6 litres

Explanation:

Let the cost of 1 litre milk be Re. 1

Milk in 1 litre mix. in 1^st can =	3	litre, C.P. of 1 litre mix. in 1^st can Re.	3
	4		4

Milk in 1 litre mix. in 2^nd can =	1	litre, C.P. of 1 litre mix. in 2^nd can Re.	1
	2		2

Milk in 1 litre of final mix. =	5	litre, Mean price = Re.	5
	8		8

By the rule of alligation, we have:

C.P. of 1 litre mixture in 1^st can C.P. of 1 litre mixture in 2^nd can

Mean Price

∴ Ratio of two mixtures =	1	:	1	= 1 : 1.
	8		8

So, quantity of mixture taken from each can =	❨	1	x 12	❩	= 6 litres.
		2

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