Difficulty: Medium
Correct Answer: 11/P + 6
Explanation:
Introduction / Context:
This age problem introduces a parameter P that represents how many times older Anita was than Ben six years ago. We are asked to express Ben s present age in algebraic form in terms of P, using the fixed current age of Anita.
Given Data / Assumptions:
Concept / Approach:
Six years ago, Anita s age was 17 - 6 = 11 years, and Ben s age was B - 6 years. The condition that Anita was P times as old as Ben can be written as:
11 = P(B - 6).
We then solve this linear equation for B in terms of P. No numerical value of P is given, so the answer must stay in symbolic form.
Step-by-Step Solution:
Anita s present age = 17 years.
Six years ago, Anita s age = 17 - 6 = 11 years.
Let Ben s present age = B years.
Six years ago, Ben s age = B - 6 years.
Given: Anita s age six years ago was P times Ben s age then.
So 11 = P(B - 6).
Divide both sides by P: B - 6 = 11 / P.
Therefore B = 11 / P + 6.
So Ben s present age is 11/P + 6 years.
Verification / Alternative check:
We can test with a simple hypothetical value of P. Suppose P = 1, meaning Anita and Ben were the same age six years ago. Then Ben s present age formula gives B = 11/1 + 6 = 17, the same as Anita s present age, which matches the interpretation that they had the same age six years ago and have both aged the same amount since then.
Why Other Options Are Wrong:
Option P/11 + 6 incorrectly inverts the fraction. Option 17 - P/6 mixes units (years) with a variable divisor, which does not follow from the equation 11 = P(B - 6). Option 17/P ignores the six-year difference entirely and does not incorporate the fixed difference between present and past ages.
Common Pitfalls:
A common mistake is to write P = 11(B - 6) or to misread P times as 11/P. Another error is forgetting to subtract 6 from both ages when going back in time. Always carefully reconstruct the situation at the earlier time before writing your equation.
Final Answer:
Ben s present age, in terms of P, is 11/P + 6 years.
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