Difficulty: Easy
Correct Answer: Incorrect
Explanation:
Introduction / Context:
The AND gate is one of the most basic logic functions. Designers use it for enabling, masking, and multi-signal qualification. Misunderstanding its HIGH-output condition can cause design errors and test misinterpretations.
Given Data / Assumptions:
Concept / Approach:
By definition, AND outputs 1 only when all inputs are 1 simultaneously. If any single input is 0, the AND output becomes 0 regardless of the other inputs. The incorrect statement confuses AND with OR, which outputs 1 when any input is 1.
Step-by-Step Solution:
1) For a two-input AND, enumerate: 00, 01, 10, 11.2) AND rule: output = 1 only for 11; otherwise output = 0.3) Therefore, “any input HIGH” causing output HIGH is false; that rule belongs to OR.
Verification / Alternative check:
Truth tables and Boolean algebra confirm AND = logical multiplication. In algebraic form for two inputs: Y = A * B, which equals 1 only if A = 1 and B = 1 together.
Why Other Options Are Wrong:
“Correct” is wrong because it restates the claim. “HIGH only when all inputs are HIGH” is actually true for AND but is not the requested evaluation of the claim; it is included as a distractor. “LOW only when all inputs are LOW” is a property of OR's complement situations, not AND in general.
Common Pitfalls:
Confusing AND with OR; assuming “any” instead of “all.” Forgetting that one LOW blocks an AND chain entirely.
Final Answer:
Incorrect
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