Consider the AND logic function used in combinational circuits. Evaluate the claim: "The output of an AND gate is HIGH when any input is HIGH."

Difficulty: Easy

Correct Answer: Incorrect

Explanation:


Introduction / Context:
The AND gate is one of the most basic logic functions. Designers use it for enabling, masking, and multi-signal qualification. Misunderstanding its HIGH-output condition can cause design errors and test misinterpretations.


Given Data / Assumptions:

  • Standard n-input AND gate.
  • Inputs are binary levels: 0 and 1.
  • We are evaluating a statement that attributes OR-like behavior to AND.


Concept / Approach:
By definition, AND outputs 1 only when all inputs are 1 simultaneously. If any single input is 0, the AND output becomes 0 regardless of the other inputs. The incorrect statement confuses AND with OR, which outputs 1 when any input is 1.


Step-by-Step Solution:
1) For a two-input AND, enumerate: 00, 01, 10, 11.2) AND rule: output = 1 only for 11; otherwise output = 0.3) Therefore, “any input HIGH” causing output HIGH is false; that rule belongs to OR.


Verification / Alternative check:
Truth tables and Boolean algebra confirm AND = logical multiplication. In algebraic form for two inputs: Y = A * B, which equals 1 only if A = 1 and B = 1 together.


Why Other Options Are Wrong:
“Correct” is wrong because it restates the claim. “HIGH only when all inputs are HIGH” is actually true for AND but is not the requested evaluation of the claim; it is included as a distractor. “LOW only when all inputs are LOW” is a property of OR's complement situations, not AND in general.


Common Pitfalls:
Confusing AND with OR; assuming “any” instead of “all.” Forgetting that one LOW blocks an AND chain entirely.


Final Answer:
Incorrect

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion