ATP energetics: Approximately how much free energy (under standard biochemical conditions) is released by hydrolysis of one mole of ATP to ADP + Pi?

Difficulty: Easy

Correct Answer: 7.3 kcal

Explanation:


Introduction / Context:
ATP hydrolysis drives countless cellular reactions by coupling. The magnitude of free energy change is important for assessing whether a coupled process can proceed spontaneously.



Given Data / Assumptions:

  • Standard biochemical conditions (pH 7, 25°C, 1 M activities) give a reference ΔG°'.
  • In vivo ΔG can be more negative due to actual ATP/ADP/Pi ratios and Mg2+ binding.
  • We use the commonly cited textbook value for ΔG°'.


Concept / Approach:
The widely accepted standard free energy change for ATP → ADP + Pi is approximately −7.3 kcal/mol (−30.5 kJ/mol). This value allows rough comparisons of energy costs and yields across metabolic steps.



Step-by-Step Solution:
Recall the typical ΔG°' magnitude. Eliminate unrealistic options in the tens to thousands of kcal/mol. Select the value closest to −7.3 kcal/mol by magnitude (reporting absolute magnitude here). Choose 7.3 kcal.


Verification / Alternative check:
Biochemistry references list −7 to −8 kcal/mol under standard conditions; cellular ΔG can reach −10 to −12 kcal/mol depending on concentrations.



Why Other Options Are Wrong:
76, 760, and 1000 kcal are orders of magnitude too large; 0.73 kcal is too small to power most biochemical work.



Common Pitfalls:
Confusing ΔG°' with in vivo ΔG; forgetting units (kcal vs kJ).



Final Answer:
7.3 kcal.

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