Alphabet jump rule: If D→H, E→J, and G→N by adding each letter’s own alphabet index (D=4, E=5, G=7), then what does K become?

Introduction / Context:
This is an alphabetic shifting puzzle where the shift amount is not constant but depends on the letter itself. The examples make it clear that each source letter jumps forward by its own position index in the English alphabet.

Given Data / Assumptions:

• D = 4; D → H (4 steps forward).
• E = 5; E → J (5 steps forward).
• G = 7; G → N (7 steps forward).
• Wraparound (beyond Z) would cycle back to A, though not needed here.

Concept / Approach:
If the rule is “letter shifts forward by its own index,” then for K (11th letter), we move forward by 11 positions: K → (11-step jump). Count carefully along the alphabet, or map to numbers mod 26.

Step-by-Step Solution:

Verification / Alternative check:
Navigating via modular arithmetic: (K=11). New index = 11 + 11 = 22 → V (22nd). Matches the manual count.

Why Other Options Are Wrong:

• U (21st) is 10 steps ahead, not 11.
• Y / Z overshoot the required jump.
• None of these: Not applicable because V fits the explicit rule.

Common Pitfalls:
Counting off-by-one when stepping letters; forgetting that the jump equals the letter’s own index.

Final Answer:
V