Symbol cipher decoding: Given A→@, B→#, C→$, D→%, E→^, M→&, N→*, O→α, S→β, R→γ, U→δ, decode “# α @ γ %”.

Difficulty: Easy

Correct Answer: BOARD

Explanation:


Introduction / Context:
This is a straightforward symbol-to-letter substitution. A partial alphabet is mapped to distinct symbols; the task is to translate a short symbol sequence into an English word using that map only.


Given Data / Assumptions:

  • Mappings: A→@, B→#, C→$, D→%, E→^, M→&, N→*, O→α, S→β, R→γ, U→δ.
  • Sequence: # α @ γ %.


Concept / Approach:
Translate symbol-by-symbol using the provided map, ensuring that each symbol is present in the mapping and yields a letter that forms a sensible English word.


Step-by-Step Solution:

# → Bα → O@ → Aγ → R% → DThus “# α @ γ %” decodes to B O A R D → “BOARD”.


Verification / Alternative check:
Check for alternative words: the exact sequence maps uniquely to BOARD with the given table; no ambiguity remains.


Why Other Options Are Wrong:

  • BOUND / BONUS / BUNCH: Require symbols not present in the given sequence or different mappings (e.g., U→δ, N→*), which do not appear.
  • None of these: Invalid because “BOARD” is a perfect decode.


Common Pitfalls:
Misreading α as A or @; ensure you distinguish between the Greek alpha (α) and the at symbol (@) since both occur in the mapping.


Final Answer:
BOARD

More Questions from Coding Decoding

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion