Difficulty: Easy
Correct Answer: 100 N/mm2
Explanation:
Introduction / Context:
In working-stress design tradition, Indian steel codes specify permissible average shear stress values for webs of rolled beams and plate girders. For unstiffened webs in Fe 250 steel, a conservative allowable shear controls web sizing and prevents shear buckling and yielding under service loads.
Given Data / Assumptions:
Concept / Approach:
The web primarily resists transverse shear. Average web shear stress τ_avg = V / (b_w * t_w) is checked against the code-specified allowable value. Traditional values adopt about 100 N/mm2 for Fe 250 to maintain adequate safety against shear yielding and instability for typical web slenderness limits.
Step-by-Step Solution:
Verification / Alternative check:
Design tables and classic examples align with the 100 N/mm2 benchmark; higher-grade steels or limit-state methods use different formulas and factors but this question targets the traditional allowable value.
Why Other Options Are Wrong:
250 N/mm2 equals nominal yield strength, not an allowable; 165 or 150 N/mm2 are higher than standard permissible shear for unstiffened webs in Fe 250 under WSD.
Common Pitfalls:
Confusing allowable stresses with limit-state design shear capacities, or using web area of the whole section instead of the clear web area.
Final Answer:
100 N/mm2
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