Steel Beams – Allowable average shear stress in an unstiffened web (Fe 250 grade steel)

Difficulty: Easy

Correct Answer: 100 N/mm2

Explanation:


Introduction / Context:
In working-stress design tradition, Indian steel codes specify permissible average shear stress values for webs of rolled beams and plate girders. For unstiffened webs in Fe 250 steel, a conservative allowable shear controls web sizing and prevents shear buckling and yielding under service loads.


Given Data / Assumptions:

  • Material: structural steel grade 250 N/mm2 (Fe 250).
  • Member: beam with unstiffened web region.
  • Design basis: permissible/allowable stress format.


Concept / Approach:

The web primarily resists transverse shear. Average web shear stress τ_avg = V / (b_w * t_w) is checked against the code-specified allowable value. Traditional values adopt about 100 N/mm2 for Fe 250 to maintain adequate safety against shear yielding and instability for typical web slenderness limits.


Step-by-Step Solution:

1) Compute factored/service shear V as per design method.2) Evaluate average shear in web: τ_avg = V / (b_w * t_w).3) Ensure τ_avg ≤ 100 N/mm2 for unstiffened web (Fe 250) in allowable stress design practice.


Verification / Alternative check:

Design tables and classic examples align with the 100 N/mm2 benchmark; higher-grade steels or limit-state methods use different formulas and factors but this question targets the traditional allowable value.


Why Other Options Are Wrong:

250 N/mm2 equals nominal yield strength, not an allowable; 165 or 150 N/mm2 are higher than standard permissible shear for unstiffened webs in Fe 250 under WSD.


Common Pitfalls:

Confusing allowable stresses with limit-state design shear capacities, or using web area of the whole section instead of the clear web area.


Final Answer:

100 N/mm2

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