Linked age statements: In ten years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B, find B’s present age.

Difficulty: Medium

Correct Answer: 39 year

Explanation:

Introduction / Context:Time-shifted age relations are best handled by setting up simultaneous equations. Translate each sentence carefully into algebra and solve the linear system for present ages.

Given Data / Assumptions:

  • Let A and B be present ages
  • A + 10 = 2 * (B − 10)
  • A = B + 9

Concept / Approach:Substitute A = B + 9 into the first equation to get B directly; then retrieve A if needed. Ensure sign handling is correct when shifting time forward/backward.

Step-by-Step Solution:

(B + 9) + 10 = 2(B − 10)B + 19 = 2B − 20 ⇒ 19 + 20 = 2B − B ⇒ B = 39Hence A = B + 9 = 48 (optional)

Verification / Alternative check:10 years from now, A = 58; 10 years ago, B = 29; twice 29 is 58 ✓.

Why Other Options Are Wrong:40, 36, 49 do not satisfy both the time-shift constraint and the current age difference of 9 years.

Common Pitfalls:Reversing the 10-year shifts or forgetting parentheses around (B − 10) when doubling.

Final Answer:39 year

More Questions from Problems on Ages

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion