Power dissipation vs. resistor ratings: A 33 Ω 0.5 W resistor and a 330 Ω 0.5 W resistor are each connected across a 12 V source (parallel branches). Which resistor(s) will overheat based on power dissipation?

Difficulty: Easy

Correct Answer: 33 Ω

Explanation:


Introduction / Context:
Selecting safe resistor power ratings prevents failures and fire hazards. This problem reinforces the calculation of power from a fixed voltage across resistors and comparison with nameplate ratings.


Given Data / Assumptions:

  • Two separate resistors are each placed directly across 12 V.
  • Ratings: 0.5 W (half-watt) each.
  • Resistances: 33 Ω and 330 Ω.


Concept / Approach:
With a known voltage across a resistor, use P = V^2 / R to compute dissipation. If the computed power exceeds the rated wattage, the part is likely to overheat in continuous service.


Step-by-Step Solution:

For 33 Ω: P = 12^2 / 33 = 144 / 33 ≈ 4.36 W >> 0.5 W → overheats.For 330 Ω: P = 144 / 330 ≈ 0.436 W < 0.5 W → within rating.Conclusion: Only the 33 Ω resistor overheats.


Verification / Alternative check:
Check current for 33 Ω: I = V / R = 12 / 33 ≈ 0.364 A; P = V * I ≈ 12 * 0.364 ≈ 4.37 W. Consistent with the V^2 / R result.


Why Other Options Are Wrong:

  • 330 Ω: Calculated power is below 0.5 W.
  • Both resistors / neither resistor: Contradicted by the computed values.


Common Pitfalls:

  • Forgetting that resistors in separate branches each experience the source voltage.
  • Using P = I^2 * R without first finding I correctly.


Final Answer:
33 Ω

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