Angular subtense of staff graduations at 20 m On a metric levelling staff, what angular subtense (in radians) does a 10 mm marking correspond to when viewed from a distance of 20 m?

Difficulty: Easy

Correct Answer: 1/2000 radian

Explanation:


Introduction / Context:
Understanding the angular size of staff graduations helps observers estimate reading precision and choose appropriate sight lengths. The basic small-angle relation links linear size, distance, and angular subtense in radians.


Given Data / Assumptions:

  • Staff graduation considered: 10 mm = 0.01 m.
  • Sight distance D = 20 m.
  • Small-angle approximation θ ≈ s / D (radians) for s ≪ D.


Concept / Approach:

Angular subtense θ (radians) equals length divided by distance for small angles. Convert the physical graduation to metres and divide by the sight distance to get θ. Express the result as a simple reciprocal in radians for easy comparison with options.


Step-by-Step Solution:

s = 0.01 m, D = 20 m.θ ≈ s / D = 0.01 / 20 = 0.0005 rad.0.0005 rad = 1/2000 rad.


Verification / Alternative check:

Convert to seconds: 0.0005 × 206265 ≈ 103.1 seconds, consistent with typical staff visibility at moderate sights.


Why Other Options Are Wrong:

1/1000, 1/1500, and 1/2500 rad differ from the computed 1/2000 rad by significant margins.


Common Pitfalls:

Forgetting to convert millimetres to metres; using degrees instead of radians when applying the small-angle relation.


Final Answer:

1/2000 radian

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