Difficulty: Easy
Correct Answer: Quartz
Explanation:
Introduction / Context:
Silica (SiO2) has several polymorphs that are stable over different temperature ranges. Knowing which phase is stable at a given temperature is important for kiln design, refractory selection, and thermal shock management.
Given Data / Assumptions:
Concept / Approach:
At room temperature up to about 870 °C, the stable polymorph is quartz (with an alpha-to-beta transition near 573 °C). At higher temperatures, tridymite becomes stable, followed by cristobalite at still higher temperatures. Thus, for temperatures below roughly 870 °C, quartz is the stable form.
Step-by-Step Solution:
Recall stability sequence with rising temperature: quartz → tridymite → cristobalite.Compare the given temperature range (below 870 °C) to the sequence.Select quartz as the correct answer.
Verification / Alternative check:
Ceramic materials references show polymorph stability fields; quartz dominates at lower temperatures under standard pressure.
Why Other Options Are Wrong:
Tridymite and cristobalite are high-temperature forms stable above quartz’s range. “None of these” is incorrect because quartz fits the condition.
Common Pitfalls:
Final Answer:
Quartz
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