Difficulty: Easy
Correct Answer: A variable can have multiple references.
Explanation:
Introduction / Context:
References are aliases. Nothing prevents multiple distinct references from aliasing the same object. This question seeks the statement that correctly captures legal and common reference usage.
Given Data / Assumptions:
Concept / Approach:
Any number of references can bind to the same object. They are simply additional names (aliases) for that object. Declaring a reference uses the & symbol in the type. Initialization is required regardless of being inside a class or function; class data members are typically initialized via constructors.
Step-by-Step Solution:
1) Consider 'int x; int &r1 = x; int &r2 = x;' → legal; two references alias x.2) Rule out '' syntax: that declares pointers, not references.3) Rule out reseating: references cannot later refer to another object.4) Rule out 'within classes': initialization is always required, not only within classes.
Verification / Alternative check:
Compile a small sample with multiple references to one variable and verify that modifying through any reference changes the same underlying object.
Why Other Options Are Wrong:
' operator': that is pointer declaration syntax.Reseating claim: contradicts the binding rule.'Must be initialized within classes': scope does not create a special exception; it is always required.
Common Pitfalls:
Assuming references are unique handles. They are not; you can create many references to the same object, which can complicate alias analysis.
Final Answer:
A variable can have multiple references.
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