C 16-bit integer constants: Which of the following is not a valid 16-bit integer constant value in C (assuming a 16-bit <code>int</code> range of −32768 to +32767)?

Introduction / Context:
This tests knowledge of integer literal ranges for a 16-bit int. While modern systems typically use 32-bit int, many exam questions still assume a 16-bit range for portability and historical reasons.

Given Data / Assumptions:

• Assumed 16-bit signed int range: −32768 to +32767.
• We examine each literal to see whether it lies within the permitted range.

Concept / Approach:
Any literal outside the stated range is invalid for assignment to a 16-bit int without causing overflow or requiring a larger integer type. The syntax of the constants is otherwise standard (leading + or − sign allowed).

Step-by-Step Solution:

Verification / Alternative check:
Consider storage width: 16-bit two’s complement cannot encode magnitude 65321; wrap-around would occur if forced, which is undefined/implementation-specific in literal typing context.

Why Other Options Are Wrong:

Common Pitfalls:

Final Answer: