Boolean forms — identifying product-of-sums (POS) Which of the following Boolean expressions is written in canonical product-of-sums (sum terms multiplied together) form?

Difficulty: Easy

Correct Answer: (A + B)(C + D)

Explanation:


Introduction / Context:
Digital logic expressions are often represented in standardized forms to simplify analysis and implementation. Two common normalized styles are sum-of-products (SOP) and product-of-sums (POS). Being able to recognize POS at a glance is fundamental for Karnaugh-map simplification, gate-level realization, and understanding how OR and AND operators structure a logic function.


Given Data / Assumptions:

  • We compare four candidate expressions.
  • Notation: + denotes OR; juxtaposition (e.g., AB) denotes AND.
  • POS means a product (AND) of sum terms (ORs of literals).


Concept / Approach:
In POS, the overall expression is an AND of terms, where each term is an OR of literals, such as (A + B + C)(A' + D). In contrast, SOP is an OR of AND terms, such as AB + A'C. By inspecting parentheses and operators, we can classify each option quickly without full expansion.


Step-by-Step Solution:

1) (A + B)(C + D): AND of two sums → POS.2) (AB)(CD): AND of products → not POS; it is purely product of products.3) AB(CD): includes a nested product term CD with AB; again product of products.4) AB + CD: OR of products → SOP, not POS.


Verification / Alternative check:
Expand option (a) using distributive property to show it becomes an OR of multiple product terms—consistent with POS expanded form.


Why Other Options Are Wrong:

  • (AB)(CD): lacks sum terms inside parentheses.
  • AB(CD): no OR inside the factors, therefore not POS.
  • AB + CD: this is SOP (sum of products), not product of sums.


Common Pitfalls:
Confusing the outer operator with the inner one; in POS, the outermost operator is AND, and each parenthesized factor must contain an OR of literals.


Final Answer:
(A + B)(C + D)

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