Difficulty: Easy
Correct Answer: (A + B)(C + D)
Explanation:
Introduction / Context:Digital logic expressions are often represented in standardized forms to simplify analysis and implementation. Two common normalized styles are sum-of-products (SOP) and product-of-sums (POS). Being able to recognize POS at a glance is fundamental for Karnaugh-map simplification, gate-level realization, and understanding how OR and AND operators structure a logic function.
Given Data / Assumptions:
Concept / Approach:In POS, the overall expression is an AND of terms, where each term is an OR of literals, such as (A + B + C)(A' + D). In contrast, SOP is an OR of AND terms, such as AB + A'C. By inspecting parentheses and operators, we can classify each option quickly without full expansion.
Step-by-Step Solution:
1) (A + B)(C + D): AND of two sums → POS.2) (AB)(CD): AND of products → not POS; it is purely product of products.3) AB(CD): includes a nested product term CD with AB; again product of products.4) AB + CD: OR of products → SOP, not POS.Verification / Alternative check:Expand option (a) using distributive property to show it becomes an OR of multiple product terms—consistent with POS expanded form.
Why Other Options Are Wrong:
Common Pitfalls:Confusing the outer operator with the inner one; in POS, the outermost operator is AND, and each parenthesized factor must contain an OR of literals.
Final Answer:(A + B)(C + D)
Discussion & Comments