Indicator diagram factor — relation between actual and theoretical mean effective pressures Given pa = actual mean effective pressure, pm = theoretical mean effective pressure, and K = diagram factor, which relation is correct?

Introduction / Context:Real engine indicator diagrams deviate from the ideal theoretical diagrams due to throttling, wire-drawing, heat losses, and valve timing. The diagram factor K captures the ratio of the actual diagram area to the theoretical diagram area, and thus relates actual to theoretical mean effective pressure (MEP).

Given Data / Assumptions:

• pm is computed from a theoretical cycle for the same boundary conditions.
• pa is obtained from the measured indicator diagram.
• Diagram factor K = actual area / theoretical area.

Concept / Approach:Since MEP is proportional to the diagram area for a given cylinder, K scales the theoretical MEP to match reality. Therefore, actual MEP equals theoretical MEP multiplied by the diagram factor.

Step-by-Step Solution:By definition: K = Area_actual / Area_theoretical.MEP ∝ diagram area (for fixed stroke and bore).Thus, pa = K * pm.Select the matching expression: pa = pm × K.

Verification / Alternative check:Worked examples compute pm from an idealized cycle and then multiply by K (often 0.7–0.9) to obtain pa before calculating indicated power.

Why Other Options Are Wrong:

• pa = pm/K inverts the effect, implying pa > pm for K < 1, which is unphysical.
• Sum or ratio forms lack basis in the definition of K.

Common Pitfalls:Treating K as an additive correction rather than a multiplicative factor derived from area ratios.

Final Answer:pa = pm × K