Noise margin formulas in logic families Which of the following equations correctly expresses the high-level noise margin of a logic family?

Difficulty: Easy

Correct Answer: VNH = VOH(min) – VIH(min)

Explanation:


Introduction / Context:
Noise margins quantify how much unwanted voltage can be superimposed on a logic level without causing an error. There are two margins: high-level (NMH or VNH) and low-level (NML or VNL). Correct formulas are essential for robust interface design and mixed-family connections.


Given Data / Assumptions:

  • VOH(min): minimum guaranteed output HIGH voltage of a driver.
  • VIH(min): minimum input voltage that will be recognized as HIGH by a receiver.
  • VIL(max): maximum input voltage that will be recognized as LOW.
  • VOL(max): maximum output LOW voltage of a driver.


Concept / Approach:

High-level noise margin is the “headroom” between what the driver guarantees at HIGH (VOH(min)) and what the receiver needs to see to accept a HIGH (VIH(min)). Thus, VNH = VOH(min) – VIH(min). Low-level noise margin is VNL = VIL(max) – VOL(max).


Step-by-Step Solution:

Compute high margin: VNH = VOH(min) – VIH(min).Compute low margin (for reference): VNL = VIL(max) – VOL(max).Select the equation that matches the high-level definition.


Verification / Alternative check:

Check any logic family datasheet; noise margins are commonly listed using these definitions, ensuring interoperability between drivers and receivers.


Why Other Options Are Wrong:

  • VNL = VIL(max) + VOL(max): incorrect operation and sign.
  • VNH = VOH(min) + VIH(min): adding values makes no physical sense for margin.
  • VNL = VOH(min) – VIH(min): that expression is the high-level margin, not low-level.


Common Pitfalls:

  • Swapping high and low symbols; remember “H” pairs with VOH/VIH, “L” with VOL/VIL.


Final Answer:

VNH = VOH(min) – VIH(min)

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