Difficulty: Easy
Correct Answer: plate area
Explanation:
Introduction / Context:Timing in first-order networks depends on the time constant tau = R * C. Since tau scales with C, any physical attribute that increases capacitance increases the time constant and slows charging/discharging (for a given R). This item asks which attribute directly influences C through the parallel-plate model.
Given Data / Assumptions:
Concept / Approach:Capacitance rises with plate area A and dielectric permittivity epsilon, and falls with greater plate separation d. Therefore, increasing plate area raises C and increases tau; decreasing area lowers C and shortens tau. Packaging, lead arrangement, or nominal voltage rating do not directly determine the capacitance value in the basic model.
Step-by-Step Solution:
1) Use C ∝ A/d to identify geometry-dependent variables.2) Plate area A is a direct multiplier of C.3) Larger C → larger tau (for fixed R).4) Therefore, plate area affects charge/discharge time.Verification / Alternative check:Manufacturing techniques (e.g., multi-layer ceramic stacks, etched foils) increase effective area to realize higher capacitance in small volumes, which directly lengthens RC time constants in timing applications.
Why Other Options Are Wrong:
Common Pitfalls:Confusing voltage rating or package with capacitance value; overlooking that dielectric constant and geometry dominate C.
Final Answer:Plate area.
Discussion & Comments