Excess-3 (XS-3) BCD — which code represents each decimal digit by its 4-bit binary value after adding 3 to that digit (i.e., code = binary(digit + 3))?

Difficulty: Easy

Correct Answer: Excess-3 code

Explanation:


Introduction / Context:
Several BCD variants exist to simplify arithmetic and error detection. Excess-3 (also written XS-3) is a self-complementing code that shifts each decimal digit by 3 before encoding it in 4-bit binary. This property eases 9’s complement and subtraction operations in certain hardware designs.


Given Data / Assumptions:

  • Per-digit BCD with 4-bit fields.
  • Mapping formula: codeword = binary(digit + 3).
  • Valid for digits 0–9 (so 3–12 in binary before mapping; 10–12 codes are still 4-bit patterns).


Concept / Approach:
By adding 3 to the decimal digit, Excess-3 ensures that the 9’s complement of a number corresponds to bitwise complement of its code, simplifying subtraction via complements. For example, digit 0 maps to 0011, 1→0100, …, 9→1100. This is not a weighted code and differs from 8421 BCD, which maps 0→0000 through 9→1001 directly without the +3 offset.


Step-by-Step Solution:

Start with digit d in 0–9.Compute d + 3.Encode the result as a 4-bit binary value.Thus obtain the Excess-3 codeword for that digit.


Verification / Alternative check:
Take d = 5: 5 + 3 = 8 → 1000; d = 9: 9 + 3 = 12 → 1100. The mapping matches standard XS-3 tables.


Why Other Options Are Wrong:

9's complement: arithmetic concept, not the code itself.8421: direct weighted BCD without the +3 shift.Gray: unit-distance code for sequencing, not decimal encoding.Two's complement: signed binary integer representation, not per-digit BCD.


Common Pitfalls:
Confusing Excess-3 with 8421 due to both using 4 bits; overlooking its self-complementing advantage for subtraction operations.


Final Answer:
Excess-3 code

More Questions from Number Systems and Codes

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion