When a host pings the loopback address (for example, 127.0.0.1 in IPv4), where does the packet actually travel in the TCP/IP stack?

Difficulty: Easy

Correct Answer: Down through the layers of the IP architecture and then up the layers again

Explanation:


Introduction / Context:
This question targets understanding of the loopback interface. The loopback address is a logical address used by a host to send IP packets to itself for testing the local TCP/IP stack without involving any external network hardware or cabling.


Given Data / Assumptions:

  • Loopback in IPv4 commonly uses 127.0.0.0/8 (typically 127.0.0.1).
  • No physical network interface is required for loopback delivery.
  • The operating system implements a virtual loopback interface in the IP stack.


Concept / Approach:

Pinging the loopback address exercises the local network stack: the packet descends from application (ping) through ICMP over IP, is directed to the loopback interface, and then is returned back up the stack to be processed locally. No external transmission takes place, and link-layer hardware is not involved.


Step-by-Step Solution:

Step 1: ICMP Echo Request is generated by the ping application.Step 2: The destination IP is a loopback address, so the IP layer routes it internally to the loopback interface.Step 3: The packet goes down the stack to IP for local handling, bypassing any physical NIC.Step 4: An ICMP Echo Reply is generated locally and delivered up the stack to the originating process.


Verification / Alternative check:

Disabling the physical NIC does not prevent a successful ping to 127.0.0.1, which confirms that no external path is used.


Why Other Options Are Wrong:

On the network / Across the wire: Loopback never leaves the host.

Through a loopback dongle: That is a hardware test tool, unrelated to IP loopback.

None of the above: Incorrect because the internal down-and-up stack path is exactly what happens.


Common Pitfalls:

Assuming loopback requires an active NIC or cabling. It does not; it is entirely virtual within the TCP/IP stack.


Final Answer:

Down through the layers of the IP architecture and then up the layers again

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