Frequency effect in series RL: When the frequency of the applied AC voltage is decreased, what happens to the total impedance magnitude of a series RL circuit?

Difficulty: Easy

Correct Answer: decreases

Explanation:


Introduction / Context:
This item tests understanding that the inductive reactance in a series RL circuit depends on frequency, directly influencing total impedance.


Given Data / Assumptions:

  • Series RL with fixed R and L.
  • AC steady state, frequency f changes.


Concept / Approach:
Impedance magnitude is Z = sqrt(R^2 + XL^2). Since XL = 2 * pi * f * L, reducing f reduces XL, thereby reducing the vector sum unless R completely dominates already (in which case Z tends toward R). In all cases with finite L, lowering f cannot increase XL, so Z does not increase.


Step-by-Step Solution:

XL = 2 * pi * f * L.Decrease f ⇒ decrease XL.Z = sqrt(R^2 + XL^2) shrinks toward R as XL decreases.Therefore, the impedance magnitude decreases.


Verification / Alternative check:
Limits: as f → 0, XL → 0 and Z → R. As f → ∞, Z → ∞ (inductor dominating). The trend with decreasing f is consistent: Z goes down.


Why Other Options Are Wrong:

  • 'increases': Opposite of XL behavior.
  • 'does not change': Would require L = 0 (no inductor), contrary to setup.
  • 'cannot be determined': Determinable from formula.


Common Pitfalls:

  • Confusing series with parallel RL behavior.


Final Answer:
decreases

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